In triangle ABC, angle A is $30^{ ext{o}}$, angle B is $60^{ ext{o}}$, and side a (opposite angle A) measures 10 units. Using the Law of Sines, calculate the length of side b (opposite angle B) to the nearest hundredth.
Recall that the Law of Sines states that $$\frac{a}{\sin(A)} = \frac{b}{\sin(B)}$$.