In triangle ABC, the angles are such that angle A is twice the size of angle B, and angle C is 30 degrees larger than angle B. If the perimeter of triangle ABC is 60 cm, what is the length of side BC?
Recall that the sum of the angles in a triangle is 180 degrees. Let angle B be represented as $x$. Then, angle A can be expressed as $2x$ and angle C can be expressed as $x + 30$. Using these expressions, find $x$ and then calculate the lengths of the sides using the Law of Sines.