In a circle with a radius of 10 cm, two chords are drawn such that they intersect at an angle of 60 degrees. The length of each chord is equal to the radius of the circle. Determine the area of the quadrilateral formed by the two chords and the two radii connecting the center of the circle to the endpoints of the chords.
Use the formula for the area of a triangle, $A = \f\frac{1}{2}ab\sin(C)$, where $a$ and $b$ are the lengths of two sides, and $C$ is the included angle.