Area of a Regular Pentagon vs. Square of Side Length

Consider a regular pentagon with a side length of $s$. A pentagon has five sides and five angles, and since it is regular, all sides and angles are equal. The formula for the area $A$ of a regular polygon can be expressed as:

$A =\frac{1}{4} n s^2\frac{1}{ an(\frac{ heta}{2})}$

where $n$ is the number of sides and $ heta$ is the measure of each interior angle. For a pentagon, $n = 5$ and the measure of each interior angle $ heta$ can be calculated using the formula $ heta =\frac{(n-2) imes 180}{n}$. Determine the relationship between the area of the regular pentagon and the square of the side length.

Let Quantity A be the area of the regular pentagon and Quantity B be the square of the side length, $s^2$. What is the relationship between Quantity A and Quantity B?