Consider a trapezoid ABCD, where AB is parallel to CD. The lengths of the bases are given as follows: AB = 10 cm and CD = 14 cm. The height of the trapezoid, the perpendicular distance between the bases, is 6 cm. Calculate the area of trapezoid ABCD.
Use the formula for the area of a trapezoid: $$A = \f\frac{1}{2}(b_1 + b_2)h$$ where $$b_1$$ and $$b_2$$ are the lengths of the two bases, and $$h$$ is the height.