A circle has a radius of 10 units. A triangle is inscribed within this circle such that one of its vertices is at the center of the circle, and the other two vertices lie on the circumference. If the angle at the center is $x$ degrees, what is the area of the triangle in terms of $x$?
To find the area of a triangle with one vertex at the center of a circle and two vertices on the circumference, use the formula:
$$ ext{Area} =\frac{1}{2} r^2 imes ext{sine}(x)$$
where $r$ is the radius of the circle.