Area of Isosceles Triangle with Given Angle

In triangle ABC, angle A is 60 degrees, and the lengths of sides AB and AC are equal. If the length of side AB is 10 units, what is the area of triangle ABC?

To solve for the area of the triangle, you may use the formula:

$$ ext{Area} =\frac{1}{2} imes ext{base} imes ext{height} $$

or the formula given by:

$$ ext{Area} =\frac{1}{2} a b imes ext{sin}(C) $$