Area of Triangle in Equilateral Setup

In an equilateral triangle ABC, each side measures 12 units. Point D is on side BC such that the ratio of BD to DC is 2:1. What is the area of triangle ABD?

Use the formula for the area of a triangle, which is given by:

Area = $$\f\frac{1}{2} \times \text{base} \times \text{height}$$