In triangle ABC, the lengths of sides AB, AC, and BC are represented by the variables $a$, $b$, and $c$, respectively. The area of triangle ABC can also be expressed using Heron's formula, which is:
$Area = \sqrt{s(s-a)(s-b)(s-c)]$
where $s = \f\frac{a + b + c}{2}$. If the sides of triangle ABC are such that $AB = 10$, $AC = 14$, and $BC = 24$, what is the area of triangle ABC?