Calculating Standard Enthalpy Change for Glucose Combustion

At a temperature of 298 K, the standard enthalpy change (ΔH^°) for the combustion of glucose (C₆H₁₂O₆) in oxygen can be described by the following reaction:

C₆H₁₂O₆(s) + 6 O₂(g) → 6 CO₂(g) + 6 H₂O(l)

Given that the standard enthalpy of formation (ΔH^°_f) for C₆H₁₂O₆(s) is -1273 kJ/mol, for CO₂(g) is -393.5 kJ/mol, and for H₂O(l) is -285.83 kJ/mol, calculate the standard enthalpy change for the combustion of glucose. Which of the following values represents the correct standard enthalpy change (ΔH^°) for this reaction?