A basketball team has 12 players, but only 5 can be on the court at any given time during a game. The coach wants to select the starting lineup for the next game. How many different ways can the coach select 5 players from the 12?
To solve this problem, you need to use the combination formula, which is given by:
$$C(n, r) = \f\frac{n!}{r!(n - r)!}$$
where $n$ is the total number of players, $r$ is the number of players to choose, and $!$ represents factorial.