In triangle XYZ, the lengths of sides XY and XZ are given as follows:
XY = 8 units, XZ = 6 units, and angle Y is 120 degrees. Calculate the length of side YZ.
Use the Law of Cosines, which states:
$$c^2 = a^2 + b^2 - 2ab \cos(C)$$
where $c$ is the side opposite angle C, and $a$ and $b$ are the other two sides.