Find the Length of Side in a Triangle Using Law of Sines

In a triangle, angle $C$ measures $60^{ ext{o}}$ and side $a$ opposite angle $A$ measures 10 units. If side $b$ is opposite angle $B$, what is the length of side $b$?

Using the Law of Sines: $$ \f\frac{a}{\sin A} = \f\frac{b}{\sin B} = \f\frac{c}{\sin C} $$, you need to find the angle $A$ or $B$ to determine the length of side $b$. Assume that side $c$ is not known and that the triangle adheres to the properties of trigonometry.