In triangle ABC, angle A measures $30^{ ext{o}}$, and angle B measures $45^{ ext{o}}$. Side a, opposite angle A, has a length of 5 units. Determine the length of side c, which is opposite to angle C. Round your answer to two decimal places.
Use the Law of Sines, which states: $$ \f\frac{a}{\sin(A)} = \f\frac{b}{\sin(B)} = \f\frac{c}{\sin(C)} $$
First, find angle C. Then, apply the Law of Sines to find c.