In triangle ABC, the lengths of sides AB and AC are 12 and 16, respectively. The angle opposite side BC is denoted as angle A. If angle A is twice the measure of angle B, what is the length of side BC?
Use the Law of Sines, which states that:
$$\f\frac{a}{\sin A} = \f\frac{b}{\sin B} = \f\frac{c}{\sin C}$$
where $a$, $b$, and $c$ are the lengths of sides opposite angles A, B, and C respectively.