In triangle ABC, angle A measures $45^ ext{o}$, and angle B measures $30^ ext{o}$. Side a, opposite angle A, measures 10 units. Using the law of sines, calculate the length of side c, opposite angle C. The law of sines states that:
$$\f\frac{a}{\sin A} = \f\frac{b}{\sin B} = \f\frac{c}{\sin C}$$
First, determine angle C. Then, use the law of sines to find side c.