Finding the Equation of a Parallel Line

Very Hard Geometry Coordinate Geometry

In a coordinate plane, consider triangle ABC with vertices at the points A(1, 2), B(5, 6), and C(3, 8).

Determine the equation of the line that is parallel to line segment AB and passes through point D(3, 4).

The slope of line segment AB can be calculated using the formula:

$slope = \f\frac{y_2 - y_1}{x_2 - x_1}$, where $(x_1, y_1)$ and $(x_2, y_2)$ are the coordinates of points A and B.

$y = \frac{2}{3}x + \frac{4}{3}$

$y = \frac{2}{3}x + 2$

$y = \frac{3}{2}x - \frac{1}{2}$

$y = \frac{3}{2}x - 3$

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