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SSAT Upper Level
Quantitative (Math)

Finding the Length of a Side in Triangle ABC Using the Law of Cosines

Hard Geometry And Measurement Triangles

In triangle ABC, the lengths of sides AB and AC are 10 cm and 14 cm, respectively. The angle between these two sides, ∠A, measures 60 degrees. To find the length of side BC, you can apply the Law of Cosines.

The Law of Cosines states that for any triangle with sides of lengths $a$, $b$, and $c$, opposite to angles $A$, $B$, and $C$, respectively, the equation is given by:

$c^2 = a^2 + b^2 - 2ab imes ext{cos}(C)$

Using this formula, what is the length of side BC (denoted as $c$) in triangle ABC?

Hint

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