In triangle ABC, the lengths of sides AB and AC are 10 cm and 14 cm, respectively. The angle between these two sides, ∠A, measures 60 degrees. To find the length of side BC, you can apply the Law of Cosines.
The Law of Cosines states that for any triangle with sides of lengths $a$, $b$, and $c$, opposite to angles $A$, $B$, and $C$, respectively, the equation is given by:
$c^2 = a^2 + b^2 - 2ab imes ext{cos}(C)$
Using this formula, what is the length of side BC (denoted as $c$) in triangle ABC?