Finding the Length of a Triangle Side Using Law of Sines

In triangle ABC, angle A measures $40^{ ext{o}}$, and angle B measures $60^{ ext{o}}$. If side AC measures 10 units, what is the length of side AB?

Use the Law of Sines to find the length of side AB, which states that $\f\frac{a}{\sin(A)} = \f\frac{b}{\sin(B)} = \f\frac{c}{\sin(C)}$ where $a$, $b$, and $c$ are the lengths of the sides opposite to angles A, B, and C respectively.