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Finding the vertex of a quadratic function

Medium Advanced Math Quadratic Equations

Consider the quadratic equation given by the function $$f(x) = 2x^2 - 4x - 6$$. To find the x-coordinate of the vertex of this parabola, you can use the vertex formula $$x = -\f\frac{b}{2a}$$, where $$a$$ and $$b$$ are the coefficients from the standard form of the quadratic equation $$ax^2 + bx + c$$.

What is the x-coordinate of the vertex of the quadratic function $$f(x)$$?

Hint

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