Consider the quadratic equation given by the function $$f(x) = 2x^2 - 4x - 6$$. To find the x-coordinate of the vertex of this parabola, you can use the vertex formula $$x = -\f\frac{b}{2a}$$, where $$a$$ and $$b$$ are the coefficients from the standard form of the quadratic equation $$ax^2 + bx + c$$.
What is the x-coordinate of the vertex of the quadratic function $$f(x)$$?