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SSAT Middle Level
Quantitative (Math)

Finding the Width of a Rectangular Garden

Hard Algebra Word Problems

A rectangular garden has a length that is 4 feet more than twice its width. The perimeter of the garden is 56 feet. What is the width of the garden?

Let the width of the garden be represented as $w$. Therefore, the length can be represented as $l = 2w + 4$. The perimeter $P$ of a rectangle can be calculated using the formula:

$$P = 2(l + w)$$

Using the given perimeter of 56 feet, you can set up the equation:

$$56 = 2((2w + 4) + w)$$

Hint

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