Finding the y-coordinate of the Vertex of a Quadratic Function

Consider the quadratic function given by the equation:

$$f(x) = 2x^2 - 4x - 6$$

To find the x-values where the function reaches its vertex, first determine the vertex using the vertex formula $$x = -\f\frac{b}{2a}$$ where $$a$$ and $$b$$ are the coefficients from the standard form of the quadratic equation $$ax^2 + bx + c$$.

After finding the x-coordinate of the vertex, substitute that value back into the original function to determine the corresponding y-coordinate. What is the y-coordinate of the vertex? Enter your answer as either a decimal or a fraction in the grid below.