In triangle ABC, the lengths of sides AB and AC are given as:
Additionally, the measure of angle A is $60^{\circ}$. Using the Law of Cosines, determine the length of side BC.
Recall that the Law of Cosines states:
$$c^2 = a^2 + b^2 - 2ab \cdot \cos(C)$$
where $c$ is the side opposite angle $C$, and $a$ and $b$ are the other two sides.