Lisa is designing a rectangular garden that will be surrounded by a walkway. The length of the garden is 3 feet more than twice its width. If the area of the garden alone is 96 square feet, what is the total area of the garden and the walkway combined if the width of the walkway is 2 feet?
Let the width of the garden be represented by $w$ (in feet). Then the length $l$ can be expressed as $l = 2w + 3$. The area of the garden, given by $A = l imes w$, equals 96 square feet, leading to the equation:
$$(2w + 3) imes w = 96.$$
After finding the dimensions of the garden, calculate the total area of the garden plus the walkway, where the walkway adds an additional width of 2 feet around the garden.