A garden in the shape of a rectangle is enclosed by a fence. The length of the garden is 12 feet more than its width. If the perimeter of the garden is 72 feet, what is the area of the garden?
Let the width be represented as $w$ feet, then the length can be represented as $w + 12$ feet. The formula for the perimeter of a rectangle is given by:
$$P = 2(l + w)$$
In this case, the perimeter $P$ is 72 feet. Using this information, you can find the dimensions of the garden.