Area of Triangle using Heron's Formula

Consider a triangle ABC with sides of lengths $a$, $b$, and $c$, opposite to vertices A, B, and C respectively. The area of triangle ABC can be expressed using Heron's formula, given by:

$$ A = ext{sqrt}(s(s-a)(s-b)(s-c)) $$

where $s$ is the semi-perimeter defined as $s = \frac{a+b+c}{2}$. If the triangle has sides of lengths $7$, $8$, and $9$, what is the area of triangle ABC?