Comparing Areas of Square and Rectangle

Consider a rectangle with a length of $12$ units and a width of $5$ units. If a square is drawn inside this rectangle such that one of its vertices coincides with the midpoint of one side of the rectangle, how does the area of the square compare to the area of the rectangle?

First, calculate the area of the rectangle:

Area of rectangle = Length $\times$ Width = $12 \times 5$.

Next, to find the area of the square, determine the maximum side length of the square that would fit within these constraints. Then, calculate the area of the square as $\text{Side length}^2$.

Compare the area of the square to the area of the rectangle and choose the appropriate option.