Consider a rectangular garden that is to be constructed with a fixed area of 540 square feet. If the length of the garden is to be 5 feet more than twice the width, what is the perimeter of the garden?

Let the width be represented by $w$ feet. Hence, the length $l$ can be expressed as $l = 2w + 5$. The area $A$ of a rectangle is given by the formula $A = l \times w$. Given that the area is 540 square feet, we have:

$540 = (2w + 5) \times w$

Find the perimeter $P$ of the rectangular garden, which is calculated using the formula $P = 2(l + w)$.