Consider a right circular cone with a base radius of 5 cm and a height of 12 cm. The volume of a cone can be calculated using the formula:
$$ V = \frac{1}{3} \pi r^2 h $$
where $r$ is the radius of the base and $h$ is the height. If the cone is then sliced parallel to the base, creating a smaller cone on top with a height of 5 cm, what is the volume of the remaining frustum (the portion of the cone that is not the smaller cone)?