In triangle ABC, angle A measures $75^ ext{o}$ and angle B measures $45^ ext{o}$. The length of side BC is 12 units. Calculate the length of side AC to the nearest hundredth of a unit. Use the Law of Sines which states that $$\frac{a}{\sin(A)} = \frac{b}{\sin(B)} = \frac{c}{\sin(C)}$$ where $a$, $b$, and $c$ are the lengths of the sides opposite angles A, B, and C respectively.

First, determine angle C using the triangle sum theorem, which states that the sum of the angles in a triangle is $180^ ext{o}$.