Potential Difference in Electric Field

A charged particle with a charge of +3 μC is placed in a uniform electric field of strength 400 N/C directed to the right. The particle experiences a force due to the electric field. To find the potential difference between two points A and B in a direction opposite to the electric field, one needs to calculate the work done in moving the charge from A to B.

Using the relationship between force, electric field strength, charge, and potential difference, what is the potential difference (V_AB) between points A and B when the particle is moved 2 meters in the opposite direction of the electric field?