Consider the quadratic equation given by:
$$2x^2 - 4x + k = 0$$
where $$k$$ is a constant. In order for this equation to have exactly one solution, the discriminant must be equal to zero. Recall that the discriminant, $$D$$, for a quadratic equation of the form $$ax^2 + bx + c = 0$$ is given by:
$$D = b^2 - 4ac$$
Determine the value of $$k$$ such that the quadratic equation has exactly one solution, and enter your answer as a decimal to the nearest hundredth.