Quadratic Function Vertex and Minimum Value

Let $$ f(x) = x^2 - 6x + 8 $$ be a quadratic function. The vertex of this function represents the minimum point on the graph. Determine the minimum value of the function by finding the value of $$ f(x) $$ at the vertex.

Recall that the vertex of a quadratic function represented by $$ f(x) = ax^2 + bx + c $$ occurs at $$ x = -\f\frac{b}{2a} $$.