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ACT
ACT Math Section

Rectangle Length and Width Calculation

Hard Preparing For Higher Math Number And Quantity

A rectangle has a length that is twice its width. If the perimeter of the rectangle is 48 units, find the dimensions of the rectangle.

Let the width be denoted as $w$. Then the length can be expressed as $2w$. The formula for the perimeter $P$ of a rectangle is given by:

$P = 2( ext{length} + ext{width})$

Substituting the expressions for length and width, set the equation to find $w$:

$48 = 2(2w + w)$

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