A rectangle has a length that is twice its width. If the perimeter of the rectangle is 48 units, find the dimensions of the rectangle.
Let the width be denoted as $w$. Then the length can be expressed as $2w$. The formula for the perimeter $P$ of a rectangle is given by:
$P = 2( ext{length} + ext{width})$
Substituting the expressions for length and width, set the equation to find $w$:
$48 = 2(2w + w)$