Consider the quadratic equation given by:
$$2x^2 - 4x - 6 = 0$$
To solve for the values of $$x$$, you can use the quadratic formula:
$$x = \f\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$
where $$a$$, $$b$$, and $$c$$ are the coefficients from the equation in the form $$ax^2 + bx + c = 0$$. In this case, identify the correct values of $$x$$ that solve the original equation.