A rectangular prism has a length of 10 cm, a width of 5 cm, and a height of 4 cm. If the length is doubled, while the width and height remain the same, what will be the new surface area of the prism?
Recall that the surface area $SA$ of a rectangular prism can be calculated using the formula:
$$SA = 2lw + 2lh + 2wh$$
where $l$ is the length, $w$ is the width, and $h$ is the height of the prism.