Triangle Law of Sines

A triangle has one angle measuring $30^{ ext{o}}$ and another angle measuring $50^{ ext{o}}$. The length of the side opposite the $30^{ ext{o}}$ angle is $x$ units. Using the Law of Sines, calculate the length of the side opposite the $50^{ ext{o}}$ angle, which we will denote as $y$. The Law of Sines states that:

$\f\frac{a}{\sin(A)} = \f\frac{b}{\sin(B)} = \f\frac{c}{\sin(C)}$

In this case, $A$ corresponds to the $30^{ ext{o}}$ angle, $B$ corresponds to the $50^{ ext{o}}$ angle, and $C$ is the third angle of the triangle. First, find the measure of angle $C$.