In triangle ABC, angle A measures $30^{ ext{o}}$ and angle B measures $60^{ ext{o}}$. The length of side a (opposite angle A) is 10 units. Using the Law of Sines, calculate the length of side b (opposite angle B).
Recall that the Law of Sines states that:
$$ \f\frac{a}{\sin A} = \f\frac{b}{\sin B} $$
Where $A$, $B$, and $C$ are the angles of the triangle and $a$, $b$, and $c$ are the respective sides opposite those angles.