Consider triangle ABC where angle A measures $60^{\circ}$ and angle B measures $75^{\circ}$. The length of side a (opposite angle A) is 10 units. Calculate the lengths of sides b (opposite angle B) and c (opposite angle C), and then determine the relationship between these sides.
Use the Law of Sines, which states that $\frac{a}{\sin A} = \f\frac{b}{\sin B} = \f\frac{c}{\sin C}$. First, compute angle C.