Finding Side Length Using Law of Sines

In triangle ABC, the measure of angle A is $30^{ ext{o}}$, and the length of side a (opposite angle A) is 5 units. If angle B measures $45^{ ext{o}}$, what is the length of side b (opposite angle B) to the nearest hundredth?

Use the Law of Sines, which states:

$$ \frac{a}{\sin A} = \frac{b}{\sin B} $$

to find the value of side b.